you need to determine the density of a ceramic statue. if you suspend it from a spring scale, the scale reads 28.4 n. if you then lower the statue into a tub of water so that it is completely submerged, the scale reads 17.0 n.

Respuesta :

The density of ceramic statue was found to be 2500kg/m³

First we calculate amount of water displayed

=  28.4 - 17.0 = 11.4N of water displaced.

Now, we calculate the volume of water displayed ,

Volume=water displaced /gravity

=11.4/9.8

Volume = 1.16kg of water.

we know that, density of water = 1000kg/m³

so, density of 1.16 kg= 1.16 x10^-3 m^3

mass of ceramic statue= 28.4 N/9.81 kg = 2.90 kg.

At last we calculate, density of ceramic statue by,

density of ceramic statue = ceramic mass/ density of water

= 2.90/(1.16 x 10^3) = 2500kg/m³

Thus, the density of ceramic statue is found to be 25kg/m³.

The measure of how densely a material is packed together is called density. As the mass per unit volume, it has that definition. Density Formula = m/V, where is the density, m is the object’s mass, and V is its volume. Density Symbol: D

If you are mixing a immiscible liquid in water, then if the density of the liquid sample is less than density of water then it it’s floats on upper surface .

To learn more about density, refer this link.

https://brainly.com/question/1354972

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