two particles, one with charge −3.77×10−6 c and the other with charge 6.91×10−6 c, are 0.0584 m apart. what is the magnitude of the force that one par

Respuesta :

The magnitude of the force that one particle exerts on the other particle is 68.6 N.

The charge of the first particle is q1.

[tex]q _{1}= - 3.77 \times 10 ^{ - 6} \: C[/tex]

The charge on the second particle is q2.

[tex]q _{2}= 6.91\times 10 ^{ - 6} \: C[/tex]

The distance between the two charged particles is d.

d = 0.0584

The magnitude of the force that one particle exerts on another particle is,

[tex]F= k \frac{q _{1} q _{2}}{(d) ^{2} }[/tex]

[tex]F=9 \times 10 ^{9} \times \frac{ - 3.77 \times 10 ^{ - 6} \times 6.91 \times ^{ - 6} }{(0.0584) ^{2} } [/tex]

F = 68.6 Newton

Therefore, the magnitude of the force that one particle exerts on another particle is 68.6 N.

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