1. An oil tank has a circular cross section of radius 2.1 metres. It is filled to a depth of 3.4 metres. a) Calculate x, the width in metres of the oil surface. 3-4 m b) What other depth of oil would give the same surface width? 2.1m
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Answer:
Step-by-step explanation:
A) We can find half of the width of the surface by applying pythagorean theorem on the right angled triangle formed by three points which are the center of the circle, the point on the circle where the the endpoints of the width and the radius meet, and the midpoint of the width.
let radius=r, width=w
[tex]r^2=(w/2)^2+(3.4-2.1)^2\\[/tex], since the distance between the origin and the midpoint of the width is 3.4m-2.1m.
[tex]-(w/2)^2=(3.4-2.1)^2-r^2, r=2.1\\-(w/2)^2=(1.3)^2-(2.1)^2\\-(w/2)^2=1.69-4.41\\-(w/2)^2=-2.72\\w/2=\sqrt{2.72}\\w=2*\sqrt{2.72}\\w=3.3 meter[/tex]
B) we can find the other depth of oil which can give the same surface area of oil if the now empty part of the cylinder is filled with oil and the now filled part of the cylinder is empty, so the other possible depth for the same surface area of oil is the diameter of the circle minus 3.4 meters:
diameter=4.2 meter, 4.2 meter-3.4 meter:
0.8 meter depth