Respuesta :
Answer: [tex]2\text{x}^4, \ 2\text{x}^7, \ 2\text{x}^{10}, \ 2\text{x}^{13}[/tex]
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Explanation:
The first term is [tex]a_1 = 2\text{x}[/tex] and the common ratio is [tex]r = \text{x}^3[/tex]
To get the second term, we multiply the first term by that common ratio
[tex]a_2 = a_1*r = 2\text{x}*\text{x}^3 = 2\text{x}^4[/tex]
Repeat a similar idea for the third term
[tex]a_3 = a_2*r = 2\text{x}^4*\text{x}^3 = 2\text{x}^{4+3} = 2\text{x}^7[/tex]
and the fourth term is
[tex]a_4 = a_3*r = 2\text{x}^7*\text{x}^3 = 2\text{x}^{7+3} = 2\text{x}^{10}[/tex]
The fifth term is
[tex]a_5 = a_4*r = 2\text{x}^{10}*\text{x}^3 = 2\text{x}^{10+3} = 2\text{x}^{13}[/tex]
Something to notice: The exponents of the first five terms are: 1, 4, 7, 10, 13. The sequence of exponents is arithmetic even though the original underlying sequence is geometric.
The reason why the exponent sequence is arithmetic is because we keep multiplying by [tex]\text{x}^3[/tex], and hence we keep adding 3 to each exponent to get the next exponent.
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To summarize, the first five terms are:
[tex]2\text{x}, \ 2\text{x}^4, \ 2\text{x}^7, \ 2\text{x}^{10}, \ 2\text{x}^{13}[/tex]
We will ignore the first term 2x since your teacher wanted you to find the next four terms after that first term (i.e. term2 through term5).
