Respuesta :

After 210 seconds, 0 e(- kt) = [SO2Cl2]0 (1 - e(- kt)) starting with 0.150M of [SO2Cl2]

[SO2]= 0.150M (1 - e) (1.48 104s 1 000 240 s)

What is concentration of a solution?

The quantity of a solute in a solvent is what we refer to in chemistry as the concentration of a solution. We refer to a solution as being concentrated when there is more solute present. Conversely, we refer to a solution as being diluted when it contains more solvent.

Utilize the integrated first order rate law, which provides the reactant sulfuryl chloride concentration as a function of time t:

([SO2Cl2]0 is the initial concentration, and k is the rate constant.) ln[SO2Cl2] = ln[SO2Cl2]0 - kt. [SO2Cl2] = e[ln[SO2Cl2]0 - kt] = e[ln[SO2Cl2]0] e(- kt) = [SO2Cl2]0 e(- kt)

The chemical equation SO2Cl2 SO2 + Cl2 describes how SO2Cl2 breaks down.

As a result, one mole of sulphur dioxide is produced for every mole of sulfuryl chloride that was lost. The relationship between these chemicals' concentration variations is as follows:

-[SO2Cl2] = [SO2] -

[SO₂Cl₂]

[SO2Cl2] - [SO2] = [SO2] - [SO2]0.

If there wasn't any sulphur dioxide at first, the concentration is as follows:

"SO2" = "SO2Cl2"

[SO2Cl2] = 0 - [SO2Cl2]

₀ - [SO₂Cl₂]

After 210 seconds, 0 e(- kt) = [SO2Cl2]0 (1 - e(- kt)) starting with 0.150M of [SO2Cl2]

[SO2]= 0.150M (1 - e) (1.48 104s 1 000 240 s)

To learn more about concentration of a solution from the given link below,

https://brainly.com/question/14404751

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