The molality of the glycerol solution is 3.854mol/kg
The number of moles of solute present in a solution equal to 1 kg or 1000 g of solvent is referred to as its molality.
Given:
Mass, m1 of glycerol = 15.01g
Mass, m2 of ethanol = 42.3g
Molar mass, mm1 of glycerol = 92.095g/mol
Molar mass, mm2 of ethanol = 46.069g/mol
To find:
Molality, m = ?
Formula:
Molality, m = moles of solute / kg of solvent
Calculations:
No. of moles of glycerol = 15.01 x (1/92.095)
n = 0.163 mols
Molality, m = 0.163 / 0.0423g
Molality, m = 3.854mol/kg
Result:
3.854mol/kg is the molality of the glycerol solution.
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