Ow many molecules of ethanol (c2h5oh) (the alcohol in alcoholic beverages) are present in 630 ml of ethanol? the density of ethanol is 0.789 g/cm3.

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12-09-2022
Chemistry

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Ow many molecules of ethanol (c2h5oh) (the alcohol in alcoholic beverages) are present in 630 ml of ethanol? the density of ethanol is 0.789 g/cm3.

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tripatsingh039 tripatsingh039 · Answer 1 · 2022-09-15T07:46:21+02:00

Taking into account the definition of density and Avogadro's number, 65.07×10²³ molecules of ethanol are present in 630 ml of ethanol.

We can calculate density to determine how much mass there is in a given volume of a substance. The quotient of a body's mass and the volume it occupies is therefore the formula for calculating density:

Density = mass / volume

So, 0.789 = mass / 630

mass =497.07grams

Then the number of moles that 110.46 g of ethanol contain is calculated by: 497.07/46 = 10.80 moles

The number of particles that make up a substance (often atoms or molecules) and may be found in a mole of that substance is known as Avogadro's Number or Avogadro's Constant. The number of particles per mole is [tex]6.022*10^{23}[/tex]. Any substance can be calculated using Avogadro's number.

So, amount of molecules= (10.80 moles× 6.023×10²³ molecules)÷ 1 mole = 65.07×10²³ molecules.

Learn more about Avogadro's number here:

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