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Calculate the change in the enthalpy of argon, in kj/kg, when it is cooled from 100 to 25oc. if neon had undergone this same change of temperature, would its enthalpy change have been any different?

Respuesta :

The change in the enthalpy of argon Almost doubles

Explanation:

Argon

Cp = Specific heat at constant volume = 0.520 kJ/kgK

T₁ = Initial temperature = 75°C

T₂ = Final temperature = 35°C

Enthalpy,

Δh = CpΔT

⇒Δh = Cp(T₂-T₁)

⇒Δh = 0.520×(35-75)

⇒Δh = -20.8 kJ/kg

Neon

Cp = Specific heat at constant volume = 1.03 kJ/kgK

T₁ = Initial temperature = 75°C

T₂ = Final temperature = 35°C

Δh = Cp(T₂-T₁)

⇒Δh = 1.03×(35-75)

⇒Δh = -41.2 kJ/kg

Enthalpy will change because the Cp value is different.

Enthalpy almost doubles.

To learn more about Enthalpy, refer

to https://brainly.com/question/25545050

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