The tall would be 2 x [tex]10^{-6}[/tex] m
Given
Use D1 and D2 to represent the old and new diameters.
D1 = 2 x [tex]10^{-8}[/tex]
D2 = 1cm
To determine how tall you'd be, we need to divide D2 by D1:
Ratio = [tex]\frac{D2}{D1}[/tex]
Substitute values for D2 and D1
Ratio = [tex]\frac{2*10^{-8} }{1cm}[/tex]
Convert cm to m
Ratio = [tex]\frac{2*10^{-8} }{0.01}[/tex]
Convert denominator to exponents
Ratio = [tex]\frac{2*10^{-8} }{10^{-2} }[/tex]
Apply the Law of indices
Ratio = [tex]2*10^{-8} *10^{2}[/tex]
Ratio = [tex]2*10^{-8+2}[/tex]
Ratio = [tex]2*10^{-6}[/tex]
Therefore [tex]2*10^{-6}[/tex]m time falls.
To learn more about average diameter tall, refer
to https://brainly.com/question/25573309
#SPJ4