How many grams of phosphorus are present in 3.51 moles of phosphorus trichloride?

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12-09-2022
Chemistry

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How many grams of phosphorus are present in 3.51 moles of phosphorus trichloride?

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bharathparasad577 bharathparasad577 · Answer 1 · 2022-09-15T07:38:53+02:00

108.81 grams of phosphorus are present in 3.51 moles of phosphorus trichloride PCl3.

The molecular formula of Phosphorus trichloride is PCl3. One mole of phosphorus trichloride contains one mole of phosphorus element. And the molar mass of phosphorus is equal to 31 grams.

So 1 mole of phosphorus trichloride contains= 31 grams of phosphorus

Using unitary method

1 mole PCl3 has = 31 grams Phosphorus

1×3.51 moles PCl3 has = 31×3.51 grams Phosphorus

3.51 moles PCl3 has = 108.81 grams of Phosphorus

Hence, 3.51 moles of phosphorus trichloride have 108.81 grams of phosphorus present in it.

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