There are 2.05×[tex]10^{25}[/tex] titantium atoms in the cube.
STEP 1. Converting inches to cm
length in cm = 2.81 in*(2.54cm/1 in)
length in cm =7.1374
STEP 2: Determining mass of cube from the density
density = mass/volume
mass = density * volume
mass = 4.50 g/cm^2*(7.1374 cm) ^3
mass = 1635.18 g
STEP 3: Converting mass of titanium cube to number of atoms
no. of. Ti. atoms = 1636.18 g Ti * ( [tex]\frac{1 mol Ti}{47.867 g}[/tex]) ([tex]\frac{6.022*10^{23} atoms}{1 mol Ti}[/tex])
no. of. Ti. atoms = 2.058*10^25 atoms
Since the given values have 3 significant figures, the final answer must be:
no. of. Ti. atoms = 2.05*10^25 Ti atoms.
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