A pure titanium cube has an edge length of 2.81 in . how many titanium atoms does it contain? titanium has a density of 4.50g/cm3.

Respuesta :

There are 2.05×[tex]10^{25}[/tex] titantium atoms in the cube.

How dense are atoms?

  • Electrons are present in atoms. True, a large portion of the mass of an atom is concentrated in its tiny nucleus, but this does not imply that the rest of the atom is empty. It rather implies that the rest of the atom has a low density.

STEP 1. Converting inches to cm

length in cm = 2.81 in*(2.54cm/1 in)

length in cm =7.1374

STEP 2: Determining mass of cube from the density

density = mass/volume

mass = density * volume

mass = 4.50 g/cm^2*(7.1374 cm) ^3

mass = 1635.18 g

STEP 3: Converting mass of titanium cube to number of atoms

no. of. Ti. atoms = 1636.18 g Ti * ( [tex]\frac{1 mol Ti}{47.867 g}[/tex]) ([tex]\frac{6.022*10^{23} atoms}{1 mol Ti}[/tex])

no. of. Ti. atoms = 2.058*10^25 atoms

Since the given values have 3 significant figures, the final answer must be:

no. of. Ti. atoms = 2.05*10^25 Ti atoms.

To learn more about dense of atoms refer to

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