The angle between sulfur-bromine bonds in SBr6 is 90°.
Sulfur hexabromide(SBr6), is a chemical compound with the hybridization of one s orbital, three p orbitals, and two d orbitals.
Hence, the hybridization of the central atom i.e, Sulfur in this compound is sp3d2.
As the compound has a hybridization of sp3d2, its shape is octahedral, as shown in the adjoining image.
As it is visible from the structure of SBr6, all angles between Sulfur and bromine are equal and their value is 90°.
Thus, the angle between sulfur-bromine bonds in SBr6 is 90°.
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