In a 20 -row theater, the number of seats in a row increases by three with each successive row. The first row has 18 seats.
c. Front-row tickets for a concert cost $ 60 . After every 5 rows, the ticket price goes down by $ 5 . What is the total amount of money generated by a full house?

Respuesta :

The most commonly used explicit of an arithmetic sequence is given as,

an = a + (n - 1) d.

Each term in the sequence can easily be solved/computed without knowing the other terms in the sequence. Now by using the given information, we can say that,

First number a1 = 18

Tolerance d = 3

Now putting the values in the given formula, we will get,

an=a1+(n-1) d

=18+(n-1)3

=3n+15

20

= ∑ 3n+15

n = 1

Sn = ∑3n+15

=3∑n+15∑1

=3 n(n+1)/2+15n

Sn =3* 20(20+1)/2+15(20)

=30 (21) +300

=630+300

=930

Total Seats 930.

Now to find the number of seats on every five lines.

5 10 15 20

= ∑ 3n+15; ∑ 3n+15 ; ∑ 3n+15 ; Ticket price for each set. $55; $50; $45

= 120 * 60 + 195 * 55 + 270 * 50 + 345 * 45

= $46950

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