11.8 grams of H₂O will be produced.
Balanced chemical equation:
MnO₂ + 4HCl → MnCl₂ + Cl₂ + 2H₂O
n(MnO₂) = 0.86 mol; amount of manganese(IV) oxide
m(HCl) = 48.2 g; mass of hydrochloric acid
n(HCl) = 48.2 g ÷ 36.5 g/mol
n(HCl) = 1.32 mol; amount of the acid
From balanced chemical equation: n(MnO₂) : n(HCl) = 1 : 4
Hydrochloric acid is limited reactant.
From balanced equation: n(HCl) : n(H₂O) = 2 : 1
n(H₂O) = 1.32 mol ÷ 2
n(H₂O) = 0.66 mol; amount of the water
m(H₂O) = n(H₂O) × M(H₂O)
m(H₂O) = 0.66 mol × 18 g/mol
m(H₂O) = 11.8 g; mass of the water
More about stoichiometry: brainly.com/question/16060199
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