The equation of the line in point-slope form, with slope equal to 3 and passing through the point located at (1 , 5), is (y - 5) = 3(x - 1).
The equation of a line can be expressed in three different forms: standard form, slope-intercept form, and point-slope form.
The standard form of an equation of a line is expressed as ax + by = c, where a and b, if all possible must be integers, are the coefficients of variable x and y, respectively, and c is a constant. Meanwhile, slope-intercept form is given by the formula y = mx + b, where m is the slope of the line and b is the y- intercept. On the other hand, given the slope m and a point on the line (x , y), we can express the equation in point-slope form, (y - y1) = m(x - x1).
Using the point slope form, plug in the values to set up the equation.
(y - y1) = m(x - x1)
where m = 3 and (x1 , y1) = (1 , 5)
(y - 5) = 3(x - 1)
In slope-intercept form, the equation of the line is:
(y - 5) = 3(x - 1)
y - 5 = 3x - 3
y = 3x + 2
In standard form, the equation of the line is:
y = 3x + 2
3x - y = -2
To learn more about equation in point-slope form: brainly.com/question/24907633
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