The empirical formula of a compound is C₂H₅O.
Take 100 grams of compound:
1) ω(C) = 53.31% ÷ 100% = 0.5331
m(C) = ω(C) × m(compound).
m(C) = 0.5331 × 100 g.
m(C) = 53.31 g.
n(C) = m(C) ÷ M(C).
n(C) = 53.31 g ÷ 12 g/mol.
n(C) = 4.44 mol; amount of carbon
2) ω(H) = 11.18 % ÷ 100% = 0.1118
m(H) = 0.1118 × 100 g.
m(H) = 11.18 g.
n(H) = 11.18 g ÷ 1 g/mol.
n(H) = 11.18 mol; amount of hydrogen
3) ω(O) = 35.51 % ÷ 100%.
ω(O) = 0.3551
m(O) = 0.3551 × 100 g
m(O) = 35.51 g.
n(O) = 35.51 g ÷ 16 g/mol.
n(O) = 2.22 mol.
4) n(C) : n(H) : n(O) = 4.44 mol : 11.18 mol : 2.22 mol /2.22 mol.
n(C) : n(H) : n(O) = 2 : 5.03 : 1
More info about empirical formula: brainly.com/question/1873039
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