0.25 is the probability a bean bag lands closer to the center of the circle than to the edge of the circle.
What is the probability in simple terms?
Let the radius of the circle be r.
Now the distsnce of the edge of the circle from the center is r units.
Now for any point lying in the circle, the sum of the distance of that point
from the center and from the nearest edge of the circle is r.
Thus, the bag will land closer to the circle if it lies within r/2 distance from the center.
Now, the area of the inner circle with radius r/2 is = [tex]\pi (\frac{r}{2})^{2} = \pi \frac{r^{2} }{4}[/tex]
The area of the actual circle = πr²
Thus, the bean bag will land closer to the center if it lies within the inner circle of area = π r²/4
Hence, the required probability = [tex]\pi r^{2} /4/ \pi r^{2}[/tex] = 1/4 = 0.25
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