The total photons needed to be absorbed are 5.533 x 10²¹ in order to melt the ice.
Given,
Wavelength = 660nm = 6.60 x [tex]10^{-7}[/tex] m
First, we find out the energy that is required to melt 5.0 x [tex]10^{2}[/tex] grams of ice. This is given by:
Energy = mass * latent heat of fusion
Energy = 5.0 x [tex]10^{2}[/tex]g x 334 J/g
Energy = 167 x [tex]10^{3}[/tex] J
So, we now have that to melt 5.0 x [tex]10^{2}[/tex] g of ice, we need 334J of energy
Next, we have to Planck's equation which is:
Energy = (number of photons x Planck's constant x speed of light) / wavelength
167 x [tex]10^{3}[/tex] J = [n * 6.64 x 10⁻³⁴ * 3 x 10⁸ ]/ 6.60 x [tex]10^{-7}[/tex]
n = 5.533 x 10²¹
5.533 x 10²¹ photons need to be absorbed by the ice in order to melt.
Planck's equation determines that the energy (E) of a photon is equal to hv = hc/λ, where v is stated as the frequency of the electromagnetic radiation and λ as its wavelength.
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