The equation of the line perpendicular to y = -²/₃x + 5 and passing through the point (6, -7) is; y = ³/₂x - 16
What is the equation of the line in slope intercept form?
We want to find the equation of the line perpendicular to y = -²/₃x + 5 and passing through the point (6, -7).
Now, the slope that is perpendicular to that line is;
m = -1/(-²/₃) = 3/2
Thus;
Equation of the new line is;
y - (-7) = 3/2(x - 6)
y + 7 = 3x/2 - 9
y = ³/₂x - 16
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