1.111 liters of water must be added to 5 kilograms of soil.
According to the statement, water percentage is equal to the ratio of water mass divided by the total mass of water and dust and multiplied by 100. Then, the initial and final percentages are defined below:
Initial percentage
y / 5 = 0.12 (1)
Final percentage
(y + x) / (5 + x) = 0.28 (2)
Then, we need to resolve the resulting system of linear equations:
y = 0.6 (1)
y + x = 1.4 + 0.28 · x
0.72 · x = 1.4 - y
x = 1.944 - 1.389 · y
x = 1.111
We need to add 1.111 kilograms of water. If the density of a kilogram per liter, the volume required in liters is:
V = (1.111 kg) / (1 kg / L)
V = 1.111 L
1.111 liters of water must be added to 5 kilograms of soil.
To learn more on system of linear equations: https://brainly.com/question/27664510
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