Refer to the number line. Find the coordinate of point X such as the ratio of MX to XJ is 2:3
Please help it’s due soon
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Explanation:
M is at 2 and J is at 18
This is a gap of 18-2 = 16
The ratio 2:3 has 2+3 = 5 parts total. Divide the gap of 16 into 5 equal parts to get 16/5 = 3.2 units
Each part is 3.2 units wide
Double this to get 2*3.2 = 6.4; the doubling is because of the "2" in "2:3"
Now add 6.4 to M = 2 to get 2+6.4 = 8.4 which is the location of point X
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Check:
Segment MX is 8.4 - 2 = 6.4 units long
Segment XJ is 18-8.4 = 9.6 units long
The ratio 6.4:9.6 is the same as 64:96 and it fully reduces to 2:3 to confirm the answer. Or you could notice that (6.4)/(9.6) = 64/96 = 2/3