Answer: the midpoint of the segment is (6,5)
Step-by-step explanation:
(2,2) (10,8)
[tex]\displaystyle\\ A_x=\frac{2+10}{2} \\\\A_x=\frac{12}{2} \\\\A_x=6[/tex]
[tex]\displaystyle\\A_y}=\frac{2+8}{2}\\ \\A_y=\frac{10}{2} \\\\A_y=5\\[/tex]
Thus, A(6,5)
