The width of the frame is 8 inches.
We are given that:
The measures of the rectangular painting are:
Length = 13 inches
width = 20 inches
Now, the frame is of uniform with around the corner.
Let it be x inches.
So the new dimensions will be:
Length = 13 + x inches
Width = 20 + x inches.
Also, we are given that:
Perimeter = 98 inches
So, we get that:
P = 2(l + b)
Substituting the values, we get that:
98 = 2 (13 + x + 20 + x)
98 = 2( 33 + 2 x)
98 = 66 + 4 x
4 x = 98 - 66
4 x = 32
x = 32 / 4
x = 8 inches.
Therefore, the width of the frame is 8 inches.
Learn more about perimeter here:
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