The distance of the image formed is -8.85 cm and the height of the image is 6.02 cm.
The position of the image formed is calculated as follows;
-1/f = 1/v + 1/u
where;
1/v = -1/f - 1/u
1/v = -/14.2 - 1/23.5
1/v = -0.112975
v = -1/0.112975
v = -8.85 cm
The height of the image formed is calculated as follows.
Use magnification equation;
image distance/object distance = image height / object height
v/u = hi/h0
8.85/23.5 = hi/16
hi = (8.85/23.5) x 16
hi = 6.02 cm
Thus, the distance of the image formed is -8.85 cm and the height of the image is 6.02 cm.
Learn more about image distance here: https://brainly.com/question/12629638
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