The required radius and error in radius is 13.8 cm and ± 0.12cm
Given that,
A machinist is required to manufacture a circular metal disk with an area of 600cm².
(a) What radius produces such a disk is to be determined
(b) If the machinist is allowed an error tolerance of ±5cm2 in the area of the disk, how close to the ideal radius in part is to be determined.
The area of a circle is given by the pie times square of the radius.
Area of circle = πr^2
Here,
a) The given area of disk = 600 cm²
πr² = 600
r = √600/3.14
r = 13.8 cm
b) an error tolerance of ± 5 cm² in the area of the disk,
So the percentage of error is 0.84%
Now, 0.84% of radius = 0.84 *13.8/100 = 0.12
The required error in radius will be ±0.12 cm
Thus, the required radius and error in radius is 13.8 cm and ± 0.12cm.
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