The calculations for the following are:
a. 51 grams.
b. 95.20 %
What is the percent yield?
Percent yield is the calculation of the difference between actual and estimated yields.
C₆H₆O₃ + 3O₂ -------> 6CO + 3H₂O
Molar mass of C₆H₆O₃
6 x 12 + 6 x 1 + 3 x 16 = 72 + 6 + 48 = 126 g per mole.
So, 125 grams is 125 / 1 26 moles = 0.992 moles of C6H6O3.
From the equation, we can see that 1 part of C₆H₆O₃ reacts with 3 parts of Oxygen gas to give 6 parts of Carbon Monoxide and 3 parts of water.
So, 1 part = 0.992 moles
Hence, 3 parts of water is 0.992 x 3 = 2.976 moles of H2O.
Molar mass of H2O = 2 x 1 + 1 x 16 = 18 grams per mole.
So, 2.976 moles of H2O has a mass of 2.976 x 18 = 53.568 grams
So, the mass of water that should have been formed = 53.568 g
Thus, the grams of the excess reactant left over is 51 grams.
Percentage yield = (51 / 53.568) x 100 is 95.20 % (approx.)
To learn more about percent yield, refer to the below link:
https://brainly.com/question/17042787
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