Question 2
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Perimeter and Area
Determine the perimeter and area of a rectangle with lengh 21 feet and width 26.1 feet.
Round your answers to the nearest hundredth as needed.
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Question 2 Question Help Read Calculator K Perimeter and Area Determine the perimeter and area of a rectangle with lengh 21 feet and width 261 feet Round your a class=

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The rectangle will have a 548.1 square foot size and a 94.2-foot periphery.

What are the rectangle's area and perimeter?

Let W be the rectangle's width and L its length.

The perimeter of the rectangle will be defined as the total length of all of its sides. So the rectangle's perimeter will be

Perimeter of the rectangle = 2(L + W) units

The area of the rectangle is the multiplication of the two different sides of the rectangle. Then the rectangle's area will be

Area of the rectangle = L×W square units

The length is 21 feet and the width is 26.1 feet.

The perimeter of the rectangle will be

P = 2 (21 + 26.1)

P = 2 x 47.1

P = 94.2 feet

The area of the rectangle will be

A = 21 x 26.1

A = 548.1 square feet

The rectangle will have a 548.1 square foot size and a 94.2-foot periphery.

More about the area and perimeter of the rectangle link is given below.

https://brainly.com/question/16572231

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