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Q5. A sample of compound contains 0.78g of K, 1.10g of Mn and 1.28g of O. Calculate the
empirical formula. (Ar. Of K=39, Ar of Mn=55, Ar of O=16)

Q5 A sample of compound contains 078g of K 110g of Mn and 128g of O Calculate the empirical formula Ar Of K39 Ar of Mn55 Ar of O16 class=

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The empirical formula of the compound will be  [tex]KMnO_4[/tex]

Empirical formula determination

The compound contains K, Mn, and O.

K = 0.78 g

Mn = 1.10 g

O = 1.28 g

Calculate the mole of each element in the compound:

K = 0.78/39 = 0.02 mole

Mn = 1.10/55 = 0.02 mole

O = 1.28/16 = 0.08 mole

Divide through by the smallest number of mole.

K = 0.02/0.02 = 1

Mn = 0.02/0.02 = 1

O = 0.08/0.02 = 4

Thus, the empirical formula of the compound is [tex]KMnO_4[/tex]

More on empirical formulas can be found here: https://brainly.com/question/14044066

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