The concentration of the chloride ion. I got 0.9 M is mathematically given as
[CL^-]=0.9mm
The reactants are listed on the left side of a chemical equation, while the products are listed on the right. Both sides of a balanced chemical equation have the same number of atoms of each element and the same overall charge.
Generally, the chemical equation for the question is mathematically given as
b) If the solution is [tex]$\mathrm{Fe}_{3}(a \omega)$[/tex]
[tex]\begin{aligned}\mathrm{FCl}_{3} & \rightarrow \mathrm{a}^{+3}+3 \mathrm{Cl}^{-} \\& 1 \mathrm{Fe}^{+3} \mathrm{~S} 3 \mathrm{al} \text { ions incota. } \\\Rightarrow\left[\mathrm{El}^{-}\right] &=\frac{3}{4} \mathrm{Cl}^{-}+4 \mathrm{Cl}^{-} \\therefore\left[\mathrm{Cl}^{-}\right] &=1.2 \mathrm{~mm} \times \frac{3}{4} \\&=0.9 \mathrm{~mm}\end{aligned}[/tex]
In conclusion, the concentration of the chloride ion. I got 0.9 M is
[CL^-]=0.9mm
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