Answer:
[tex]\frac{28}{45} .[/tex]
Step-by-step explanation:
way_1:
according to the condition the probability for the 1st computer is 8/10=4/5;
for the 2d computer is 7/9. Then the final probability is P=4/5 * 7/9=28/45;
way_2:
the required probability can be calculated according the formula:
[tex]P=\frac{no-cases}{total-cases};[/tex]
then
[tex]P=\frac{C^2_8}{C^2_{10}} =\frac{2!8!8!}{2!6!10!}=\frac{28}{45} .[/tex]
