The equation of the line is y = mx + 5.
We have a line L that passes through the point P(- 3, 5) with slope (say m).
We have to find the equation of this line L.
The general equation of the line is given by - y = mx + c, where m is the slope of line.
On comparing the general equation with the equation of the line given, we get -
m = 1
According to the question -
Point through which the line passes - P(-3, 5)
y - intercept = c = 5
Slope of the line - m
Substituting the values in the general equation of line, we get -
y = mx + 5
Hence, the equation of the line is y = mx + 5.
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