Question 2 (1 point)
Mr. Franklin determined that the mean diving score for
Diver 1 was 8.1 with a standard deviation of 1.07. The
mean diving score for Diver 2 was 8.8 with a standard
deviation of 2.24. Which conclusion can be made about the
scores of the divers?

O a
Diver 2 had scores that were less spread out around
the mean than Diver 1.

Ob
Diver 1 and Diver 2 had scores that were equally
spread around the mean.

O Diver 1 had scores that were less spread out around
the mean than Diver 2.

Respuesta :

The correct conclusion is Diver 2 had scores that were less spread out around the mean than Diver 1.

The question has to do with mean deviation

What is mean deviation?

The mean deviation is the measure of the spread or the difference between the mean and the standard deviation d = |X - σ| where

  • X = mean and
  • σ = standard deviation

How to find out which conclusion is true?

Since  the mean diving score for Diver 1 was X₁ = 8.1 with a standard deviation of σ₁ = 1.07. The spread or deviation ,d₁ = |X₁ - σ₁|

= |8.1 - 1.07|

= |7.03|

= 7.03

Since  the mean diving score for Diver 2 was X₂ = 8.8 with a standard deviation of σ₂ = 2.24. The spread or deviation ,d₂ = |X₂ - σ₂|

= |8.8 - 2.24| =

|6.56|

= 6.56

Since d₂ = 6.56 < d₁ = 7.03, we see that Diver 2 had scores that were less spread out than Diver 1.

So, the correct conclusion is Diver 2 had scores that were less spread out around the mean than Diver 1.

Learn more about mean deviation here:

https://brainly.com/question/27868686

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