The probability that 17 adults in a sample of 100 adults pass the fitness test is 0. 0106. option B
Probability can be described as:
Let's use the binomial formula to solve this problem.
[tex]P(X) = \frac{n!}{x!(n - x) !} * p^x( 1- p) ^n^-^x[/tex]
Where:
Now, let's find the probability:
[tex]P(17) = \frac{100!}{17!( 100 - 17)!} * 0. 1 ( 1- 0.1 ) ^1^0^0 ^- ^1^7[/tex]
P = 0. 0106
Hence, the probability that 17 adults in a sample of 100 adults pass the fitness test is 0. 0106. option B
The complete question is:
It is known that 10% of adults can pass a fitness test. What is the probability that 17 adults in a sample of 100 adults pass this fitness test?
A. 0.9900
B. 0.0106
C. 0.1000
D. 0.0343
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