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A certain solar panel is capable of absorbing 750J of light energy every second, and converting 150J of that energy into electrical energy. a. How much energy is ‘wasted’ in the form of heat by the solar panel every second? b. What is the efficiency of this solar panel?

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The efficiency of the solar panel is 20%.

What is the wasted energy?

Now we know that energy is the ability to do work. The energy that is put into a good use is the one that is able to do reasonable work. The one that does not do work is said to be wasted.

Hence;

Energy that is absorbed =  750J

Amount of energy converted = 150J

Wasted energy = 750J  - 150J = 600 J

The efficiency of the solar panel = 150J/ 750J  * 100/1

= 20%

Learn more about efficiency of a solar panel:https://brainly.com/question/26983085

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