the parallel linear equation to y = (4/3)*x + 8 that passes through (-6, -6) is:
y = (4/3)*x + 2
How to find the equation of the parallel line?
A general line equation can be written as:
y = a*x + b
Where a is the slope and b is the y-intercept.
Two linear equations are parallel if the slope is the same, but the y-intercept is different.
Then, an equation parallel to y = (4/3)*x + 8
Will be of the form:
y = (4/3)*x + c
Where c ≠ 8.
Now, we also want our line to pass through the point (-6, -6), then we must have:
-6 = (4/3)*(-6) + c
With that, we can find the value of c.
-6 + 6*(4/3) = c
6*(-1 + 4/3) = c
6*(1/3) = c = 2
Then the parallel linear equation to y = (4/3)*x + 8 that passes through (-6, -6) is:
y = (4/3)*x + 2
If you want to learn more about linear equations, you can read:
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