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Consider the following balanced reaction between hydrogen and nitrogen to form ammonia:
3H2(g) + N2(g) → 2NH3(g)
How many moles of NH3 can be produced from 29.0 mol of H₂ and excess N₂?
Express the number of moles to three significant figures.

Respuesta :

Oseni

The number of moles of NH3 that can be produced is 19.3 moles.

Stoichiometric problem

From the balanced equation of the reaction, the mole ratio of H2 reacted and NH3 produced is 3:2.

This means that for every 1 mole of H2 that reacts, 2/3 mole of NH3 will be produced.

Now, we have 29.0 moles of H2 reacting. If 1 mole of H2 produces 2/3 moles NH3, then 29 moles of H2 will produce:

                       29 x 2/3 = 19.3333 moles of NH3

To three significant figures, 19.333 moles will be 19.3 moles.

More on stoichiometric problems can be found here: https://brainly.com/question/14465605

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