Using PT in the Coordinate System
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Answer:
[tex]d = \sqrt{40} [/tex]
Distance between two points is given by the formula,
[tex]d= \sqrt{((x_2 - x_1)^{2} + (y_2 - y_1)^{2} )}[/tex]
Let,
[tex] \sf Point \: 1 = (x_1,y_1)= (-3,2)[/tex]
[tex]\sf Point \: 2 = (x_2,y_2)= (3,0)[/tex]
Substituting the given coordinate in above formula,
[tex]d= \sqrt{((3 - ( - 3))^{2} + (0 - 2)^{2} )}[/tex]
[tex]d = \sqrt{ {6}^{2} + ({ - 2})^{2} }[/tex]
[tex]d = \sqrt{36 + 4} [/tex]
[tex]d = \sqrt{40} [/tex]
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