i) The volume of oxygen gas remaining will be 20 cm3
ii) The volume of carbon dioxide produced will be 20 cm3
Volume ratios
Gases are known to react in volume ratios at standard temperature and pressure. So, we are assuming that the illustrated reaction happened at STP.
From the balanced equation, the mole ratio of ethene and oxygen is 1:3. This means that for every 1 cm3 of ethene, 3 cm3 of oxygen is required.
With 10 cm3 of ethene, 30 cm3 of oxygen will be required. But 50 cm3 was used for the experiment.
i) Remaining oxygen = 50 - 30 = 20 cm3
ii) The mole ratio of ethene and carbon dioxide is 1:2. Thus, for 10 cm3 ethene, the volume of carbon dioxide produced will be:
10 x 2 = 20 cm3
More on volume ratios of gases can be found here: https://brainly.com/question/4066401
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