13. In Singapore, the legal limit for the concentration of alcohol (ethanol, C,H,OH) in the blood is 80 mg in 100 cm³ of blood. Complete the table by calculating the concentration of alcohol in mol dm-3 in a person at various states of intoxication. You may assume that 1 dm³ of blood contains 1 dm³ of water.​

13 In Singapore the legal limit for the concentration of alcohol ethanol CHOH in the blood is 80 mg in 100 cm of blood Complete the table by calculating the con class=

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The concentrations in mol/dm³ would be 0.002, 0.04, 0.007, and 0.01 respectively.

Concentration in mol/dm3

Since  1 dm³ of blood is taken as containing  1 dm³ of water, it means that the concentration levels are in mg/dm³.

Thus, we are tasked with the job of converting from mg/dm³ to mol/dm³.

Recall that: mole = mass in grams/molar mass in gram/mole

Molar mass of ethanol = 46.07 g/mol

80 mg of ethanol = 0.08 g = 0.08/46.07 = 0.002 mol

200 mg of ethanol = 0.2 g - 0.2/46.07 = 0.004 mol

300 mg = 0.3 g = 0.3/46.07 = 0.007 mol

500 mg = 0.5 g = 0.5/46.07 = 0.01 mol

Therefore, the respective concentrations in mol/dm³ would be 0.002, 0.04, 0.007, and 0.01 respectively.

More on concentrations can be found here: https://brainly.com/question/13872928

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