contestada

find the point of discontinuity of function f(x) = (x^2-25)÷(x-5) and remove the discontinuity

Respuesta :

bunnuika

Step-by-step explanation:

(x²-25)/(x-5)

for it to be continous x-5≠0

•°•X≠5

if x=5 the Denominator we b zero ,because any thing divide by zero is undefined

so we have:

(x²-25)/(x-5)=(x-5)(x+5)/(x-5) by differences of two square

so we have:

(x+5) as point of discontinuity

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