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What is the molar mass of a gas if 16.0 l of the gas has a mass of 19.0 g at 765 torr and 20.0 °C? a. 28.3 g b. 0.0352 g c. 1.94 g d. 26.8 g

Respuesta :

Answer: a

Explanation:

Assuming the gas is an ideal gas, we can use the eqn PV = nRT to find the number of moles of the gas (n).

PV = nRT

n (no. of moles of gas) = PV/RT

R = 62.363 L⋅Torr/K⋅mol

(765) x (16.0 L)/(62.363) x (293.15 K) = 0.6721470629 moles

To find the mass of 1 mole of the gas (molar mass) = 19.0g / 0.6721470629 moles = 28.26762334 g/mol

                                     = 28.3 g/mol (3 s.f.)

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