contestada

nitial mass of water, at its boiling point, is 0.8 kg. 4 kW of heater is used to boil it completely. Assuming the specific latent heat of vaporization of water is 2MJ/kg, what is the time taken to vaporize all the water

Respuesta :

onyebuchinnaji

The  time taken to vaporize all the water is 400 seconds.

Total heat required to vaporize the water

The total heat required to vaporize the water is calculated as follows;

E = Lm

where;

  • L is latent heat of vaporization of water
  • m is mass of water

E  = 2 x 10⁶ J/kg x 0.8 kg

E = 1,600,000 J

Time taken to vaporize all the water

The time taken to vaporize all the water is calculated as follows;

E = power x time

time = E/power

time = ( 1,600,000 J) / (4,000 J/s)

time = 400 seconds

Thus, the  time taken to vaporize all the water is 400 seconds.

Learn more about heat of vaporization of water here: https://brainly.com/question/26306578

#SPJ1

Otras preguntas