The mean of the discrete distribution that models this situation is of 2.98.
The expected value of a discrete distribution is given by the sum of each outcome multiplied by it's respective probability.
Considering the table, the probability distribution is given by:
Hence the mean is given by:
E(X) = 4 x 0.4 + 3 x 0.32 + 2 x 0.17 + 1 x 0.08 + 0 x 0.03 = 2.98.
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