9 bits would you need to store the number 500.
What is bite?
The number of digit in base 2 required to represent 500 base 10 can be found with the equation.
b=log2(500)
The only problem with this is that unless the operand is exactly a power of two you will get a fractional number of bits What you really want is the next whole number of bits greater than that indicated by the equation. This is indicated by using the “ceiling” notation.
b= ⌈log2(500)⌉
log2(500)= 8.96...
⌈8.96…⌉= 9
Thus, a minimum of 9 bits are required to represent 500 base 10.
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