Is anyone able to solve this problem?
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Answer:
y = 2√5.
Step-by-step explanation:
Consider the smallest triangle.
Applying Pythagoras theorem:
y^2 = x^2 + 2^2
The smallest and larger triangle (the one with one side = 8) are similar so we have the proportions :
x/2 = 8/x
---> x^2 = 16
---> x = 4.
Therefore , substituting for x in the first equation:
y^2 = 4^2 + 2^2
---> y^2 = 20
---> y = √20
---> y = 2√5.
Answer:
y = 2[tex]\sqrt{5}[/tex]
Step-by-step explanation:
using the Altitude- on- Hypotenuse theorem
(leg of big Δ )² = (part of hypotenuse below it ) × ( whole hypotenuse )
y² = 2 × (2 + 8) = 2 × 10 = 20 ( take square root of both sides )
y = [tex]\sqrt{20}[/tex] = [tex]\sqrt{4(5)}[/tex] = [tex]\sqrt{4}[/tex] × [tex]\sqrt{5}[/tex] = 2[tex]\sqrt{5}[/tex]