The pickering nuclear power plant has a power energy 3100 mw. How much energy in mj is lost during one day operation?

Respuesta :

Answer:

2.6784x10^8 mega joules

Explanation:

joules = watts * seconds

Electrical Energy = Power x Time

Electrical Energy (joules) = watts x seconds in a day

seconds in day 86400 seconds

3100 megawatts = 3.1x10^9 watts

Electrical Energy (joules) = 3.1x10^9 x 86400

Electrical Energy (joules) = 2.6784x10^14 joules

2.6784x10^14 joules = 2.6784x10^8 mega joules

edinformaticscom

https://brainly.com/question/12666523