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A simple pendulum suspended in a rocket ship has a period [tex]T_{0}[/tex]. Assume that the rocket ship is near the earth in a uniform gravitational field.
True or false:
1. If the ship moves upward with a constant velocity, the period increases.
2. If the length of the pendulum is doubled, the new period will be: square root of 2 times [tex]T_{0}[/tex].
3. If the ship accelerates upward, the period increases.
4. If the ship accelerates downward at 9.81 [tex]m/s^{2}[/tex], the pendulum will no longer oscillate.
5. If the mass of the pendulum is halved, the period decreases.

Respuesta :

The answers to the true and false questions for the pendulum are all below;

1 If the ship moves upward with a constant velocity, the period increases. FALSE(The duration of the time period will not change even if there is no acceleration of the ship.)

2. If the length of the pendulum is doubled, the new period will be square root of 2 times .T_0

TRUE(The time period, T, is calculated as 2 pi times the square root of a fraction of the length g; hence, when the length is doubled, the time period is calculated as square root 2 times.

3. If the ship accelerates upward, the period increases.

FALSE(Due to the fact that the value of 'g' is becoming more effective)

4. If the ship accelerates downward at 9.81, the pendulum will no longer oscillate.

TRUE(The effective value of g is equal to zero. As a result, the duration of time becomes endless)

5. If the mass of the pendulum is halved, the period decreases.

FALSE(The presence of mass has no impact on the duration of the time period.)

What is a simple pendulum?

Generally, A perfect pendulum would have a point mass hanging on an inextensible, completely flexible thread, and would be allowed to freely vibrate without causing any friction.

Read more about a simple pendulum

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