The correct option is b. 9.7 meters/second².
The magnitude of the acceleration of the falling ball is 9.7 meters/second².
Acceleration is the rate for which velocity changes over time, both in terms of speed and direction. A point or object travelling in a straight path gets accelerated if it accelerates or decelerates.
The final velocity of a falling ball, v = 33 m/s
The ball's initial velocity, u= 0 m/s
The time it required for the ball to arrive at the ground, t = 3.4 seconds
The ball's acceleration during the fall Equals 'a'.
The formula for acceleration is;
acceleration = (final velocity - initial velocity)/time
Substituting the values in the formula;
a = (33 - 0)/3.4
a = 9.7
Therefore, the rate of acceleration of the falling ball is 9.7 m/s².
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