If you have 50 grams of H2SO4 and excess
Al, how many grams of Al2(SO4)3 are
produced during the following reaction?
2 Al + 3 H2SO4 → Al2(SO4)3 + 3 H2

Respuesta :

The answer is 0.65mol [tex]Alx_{2} (So_{4} )_{3}[/tex].

What is the molar mass?

  • The mass in grams of one mole of a chemical is its molar mass. A mole is the measurement of the number of things, such as atoms, molecules, and ions, that are present in a substance. Any substance's mole is. Molecules, 6.022 10 23.
  • Divide each element's atomic weight (found in the periodic table) by the number of that element's atoms in the compound. 3. Add up the totals, and then follow the number with the units of grams/mole.
  • The mass of every atom in a molecule, expressed in grams per mole, is known as the molar mass. We first obtain the atomic weights of the different elements in a periodic table to compute a molecule's molar mass. Then, we multiply the total number of atoms by each one's atomic mass.

How many grams of Al2(SO4)3 are produced during the following reaction?

2 Al + 3 H2SO4 → Al2(SO4)3 + 3 H2

Molar mas:26.98 →341.15g/mol

All take 35g.

Moles of aluminum=35/26.98=1.29mol.

2mole of aluminum will give=1/2*1.29=0.65

Therefore, 0.65mol [tex]Alx_{2} (So_{4} )_{3}[/tex].

To learn more about Molar mass, refer to:

https://brainly.com/question/837939

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