0.13M
the molar concentration in the equilibrium mixture is 0.13M.
We know that the balanced reaction equation is:
CO(g)+H2O(g)⇋CO2(g)+H2(g)
The initial molarity values are:
[CO]=[H2O]=2.0 mol/10.0 L=0.20M
We can give equilibrium constant expression to be:
Kc=4.0=[CO2][H2] / [CO][H2O]
Since there are initially no products, the reaction must move to the right in order to attain equilibrium. We find the solution to the expression for the needed molarity change x:
4.0=(x)(x) / (0.20M−x)2
4.0=x^2 / 0.040−0.40x+x2
0.16−1.6x+4.0x^2=x^2
3x^2−1.6x+0.16=0
x=0.13M
Therefore at equilibrium we will have:
[H2]=x=0.13 M
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